>>440
∫[0,1]x^2 arcsin(x)dx
= (1/3)[x^3 arcsin(x)]_[0,1] - (1/3)∫[0,1]x^3/√(1-x^2)dx
（t = √(1-x^2) と痴漢）
= (π/6) - (1/3)∫[0,1](1-t^2)dt
= (π/6) - (1/3)[t-(t^3/3)]_[0,1]
= (π/6) - (2/9)