y=2x-x^2,y=(4/3)xで囲まれた図形の面積を求めよ

∫[0,(2/3)]{(2x-x^2-(4/3)x}dx
=∫[0,(2/3)]{-x^2+(2/3)x}dx
=-∫[0,(2/3)]{x(x-(2/3))}dx
=-∫[0,(2/3)]{x-0}{x-(2/3)}dx
=-{-(1/6)}{2/3}^3

あってますか？