>>424
x + y = 3 - z

1/x + 1/y = 1/3 - 1/z
(x + y)/(xy) = (z - 3)/(3z)
xy = -3z

解と係数の関係より、x,yはt^2 -(3-z)t - 3z = 0の解なので、
x = 3, y = -z

よって、x^3 + y^3 + z^3 = 3^3 - z^3 + z^3 =27