>>63
(1)#include <stdio.h>
int main()
{
int n, m;
for(n = 1; n <= 1729; n++)
for(m = 1; m <= n; m++)
if(n*n*n + m*m*m == 1729)
printf("%d^3 + %d^3 = 1729\n", n, m);
return 0;
}