#include <stdio.h>
main()
{
char x[3][7] = {"first","second","third"};
char *z[3] = {"first","second","third"};
char **p;


p = z;
p++;
�@ printf("%c\n",**p);
�A printf("%s\n",*p+1);
�B printf("%s\n",*(p+1)+1);

これだと xの要素数は21個で ポインタ配列zの要素数は19個
�@�A�Bのprintfの表示は �@がs �Aがecond �Bがhird
でいいですかね?