>>766
問2
#include<stdio.h>
int main(void)
{
  int x = 1;
  double s = 1.0, ss = 1.0;
  do s += (ss /= (double)x++); while (ss >= 0.00000001);
  printf("S = %f\n", s);
}

問3
#include<stdio.h>
int main(void)
{
  int n = 0, sum = 0;
  do sum += ++n; while (sum < 10000);
  printf("sum:%d n:%d", sum - n, n - 1);
}