>210

試してみました。

w=k_1e_1∧e_2∧e_3+k_2e_1∧e_2∧e_4+k_3e_1∧e_3∧e_4+k_4e_2∧e_3∧e_4=k_1e_1+k_2e_2+k_3e_3+k_4e_4.
一方,
w=h(q_11e_1∧e_2∧e_3+q_12e_1∧e_2∧e_4+q_13e_1∧e_3∧e_4+q_14e_2∧e_3∧e_4)
∧(q_21e_1∧e_2∧e_3+q_22e_1∧e_2∧e_4+q_23e_1∧e_3∧e_4+q_24e_2∧e_3∧e_4)
∧(q_31e_1∧e_2∧e_3+q_32e_1∧e_2∧e_4+q_33e_1∧e_3∧e_4+q_34e_2∧e_3∧e_4)
= h(q_11v_1+q_12v_2+q_13v_3+q_14v_4)∧(q_21v_1+q_22v_2+q_23v_3+q_24v_4)∧(q_31v_1+q_32v_2+q_33v_3+q_34v_4)
=hΣ_{σ∈Sym(4),σ(1)<σ(2)<σ(3)}sgn(σ)q_{1σ(1)}q_{2σ(2)}q_{3σ(3)}v_σ(1)∧v_σ(2)∧v_σ(3)
=h(q_11q_22_q_33-q_11q_23_q_32+q_12q_21_q_33+q_12q_23_q_31+q_13q_21_q_32-q_13q_22_q_31)e_1∧e_2∧e_3
+(q_11q_22_q_34-q_11q_24_q_32+q_12q_21_q_34 -q_12q_24_q_31-q_14q_21_q_32+ q_14q_22_q_31)e_1∧e_2∧e_4
+(q_11q_23_q_34-q_11q_24_q_33+q_13q_21_q_34+q_13q_24_q_31+q_14q_41_q_33-q_14q_23_q_31)e_1∧e_3∧e_4
+(q_12q_23_q_34-q_12q_24_q_33+q_13q_22_q_34 -q_13q_24_q_32-q_14q_22_q_33+ q_14q_23_q_32)e_2∧e_3∧e_4
=h(q_11q_22_q_33-q_11q_23_q_32+q_12q_21_q_33+q_12q_23_q_31+q_13q_21_q_32-q_13q_22_q_31)e_1
+(q_11q_22_q_34-q_11q_24_q_32+q_12q_21_q_34 -q_12q_24_q_31-q_14q_21_q_32+ q_14q_22_q_31)e_2
+(q_11q_23_q_34-q_11q_24_q_33+q_13q_21_q_34+q_13q_24_q_31+q_14q_41_q_33-q_14q_23_q_31)e_3
+(q_12q_23_q_34-q_12q_24_q_33+q_13q_22_q_34 -q_13q_24_q_32-q_14q_22_q_33+ q_14q_23_q_32)e_4.
だから,

k_1/h=

|q_11,q_21,q_31|
|q_12,q_22,q_32|
|q_13,q_23,q_33|


k_2/h=

|q_11,q_21,q_31|
|q_12,q_22,q_32|
|q_14,q_24,q_34|


k_3/h=

|q_11,q_21,q_31|
|q_13,q_23,q_33|
|q_14,q_24,q_34|


k_4/h=

|q_12,q_22,q_32|
|q_13,q_23,q_33|
|q_14,q_24,q_34|


となりましたが,これらから

q_11,q_12,…,q_34それぞれはどのようにしてk_1,k_2,k_3,k_4で表させるのでしょうか?