高校数学の質問スレPART367
■ このスレッドは過去ログ倉庫に格納されています
0261１３２人目の素数さん
2014/02/23(日) 01:01:23.77S[n+1] = S[n]+a[n]
a[n]=(1-2*S[n])/(2n-1)
2*S[n+1]+(2(n+1)-1)*a[n+1]=1
2(S[n]+a[n]) + (2n+2-1)*a[n+1]=1
2{(1-(2n-1)*a[n])/2} + 2a[n] +(2n+1)*a[n+1]=1
(1-(2n-1)*a[n]) + 2a[n] +(2n+1)*a[n+1]=1
1 - 2n*a[n] - a[n] + 2a[n] +(2n+1)*a[n+1]=1
-2n*a[n]+a[n] + (2n+1)*a[n+1] = 0
(2n-1)a[n] = (2n+1)a[n+1]
a[n]/a[n+1] = (2n+1)/(2n-1)
{(2n-1)/(2n+1)} * a[n] = a[n+1]
■ このスレッドは過去ログ倉庫に格納されています