分からない問題はここに書いてね355
■ このスレッドは過去ログ倉庫に格納されています
0162132人目の素数さん
2011/06/25(土) 17:22:42.721) tan(x) = sin(x)/cos(x)
= {x -(1/3!)x^3 +(1/5!)x^5 - ・・・}/{1 -(1/2!)x^2 +(1/4!)x^4 -(1/6!)x^6 + ・・・}
= x + (1/3)x^3 + (2/15)x^5 + O(x^7)
2) sin(x) = x - (1/3!)x^3 + (1/5!)x^5 - ・・・・,
x・sin(x) = x^2 - (1/3!)x^4 + (1/5!)x^6 - ・・・・,
e^(x・sin(x)) = 1 + x・sin(x) + (1/2!){x・sin(x)}^2 + (1/3!){x・sin(x)}^3 + ・・・・
= 1 + x^2 +(1/3)x^4 + (1/120)x^6 + O(x^8),
3) x/(e^x -1) = x/{Σ[k=1,∞] (1/k!)x^k }
= 1/{1 + (1/2)x + (1/6)x^2 + (1/24)x^3 + (1/120)x^4 + ・・・・ }
= 1 -(1/2)x +(1/12)x^2 -(1/720)x^4 + O(x^6)
(別解)
x/(e^x -1) + (x/2) は偶関数。
x/(e^x -1)= (x/2)(e^x +1)/(e^x -1) - (x/2)
= (x/2){e^(x/2) + e^(-x/2)}/{e^(x/2) - e^(-x/2)} - (x/2)
= (x/2)coth(x/2) - (x/2)
= 1 -(1/2)x +(1/12)x^2 -(1/720)x^4 + O(x^6)
■ このスレッドは過去ログ倉庫に格納されています