>>641 こうじゃね？
f()=1+1=2

f(0)=f()+f()=2+2=4
f(1)=f(0)+f(0)=4+4=8
f(2)=f(1)+f(1)=8+8=16
f(3)=f(2)+f(2)=16+16=32
f(4)=f(3)+f(3)=32+32=64
f(n)=2^(n+2)
f(64)=2^66

f(0,0)=f(f(0))=f(4)=64
f(1,0)=f(f(0,0))=f(64)=2^66
f(2,0)=f(f(1,0))=f(2^66)=2^(2^66)
f(3,0)=f(f(2,0))=f(2^(2^66))=2^(2^(2^66))
f(4,0)=f(f(3,0))=f(2^(2^(2^66)))=2^(2^(2^(2^66)))

f(0,1)=f(f(0,0),0)=f(64,0)
f(1,1)=f(f(0,1),0)=f(f(64,0),0)
f(2,1)=f(f(1,1),0)=f(f(f(64,0),0),0)
f(3,1)=f(f(2,1),0)=f(f(f(f(64,0),0),0),0)
f(4,1)=f(f(3,1),0)=f(f(f(f(f(64,0),0),0),0),0)

f(0,2)=f(f(0,1),1)=f(f(64,0),1)
f(1,2)=f(f(0,2),1)=f(f(f(64,0),1),1)
f(2,2)=f(f(1,2),1)=f(f(f(f(64,0),1),1),1)
f(3,2)=f(f(2,2),1)=f(f(f(f(f(64,0),1),1),1),1)
f(4,2)=f(f(3,2),1)=f(f(f(f(f(f(64,0),1),1),1),1),1)