>>959

r^10 = x とでも置く

(a(x-1))/(r-1) = 4 …�@
(ax(x^2-1))/(r-1) = 48…�A

 x^2-1 = (x+1)(x-1) だったよね

(ax(x+1)(x-1))/(r-1) = 48

{ (a(x-1))/(r-1) } x(x+1) = 48  { }カッコ内は�@だ!
{ 4 } x(x+1) = 48
x(x+1) = 12

x を元に戻して
r^10(r^10+1) = 12