高校生のための数学の質問スレPART239
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0451132人目の素数さん
2009/08/02(日) 13:54:19b=sin^2(72°)
n=1のとき
(a^(-1)+b^(-1))(a+b)
=(a+b)^2/(ab)
=(sin^2(36°)+sin^2(72°))^2/(sin^2(36°)sin^2(72°))
=(sin^2(36°)+4sin^2(36°)cos^2(36°))^2/(sin^2(36°)4sin^2(36°)cos^2(36°))
=(1+4cos^2(36°))^2/(4cos^2(36°))
=(1+8cos^2(36°)+16cos^4(36°))/(4cos^2(36°))
=(1+8(1-sin^2(36°))+16(1-sin^2(36°))^2)/(4(1-sin^2(36°)))
=(1+8-8sin^2(36°)+16-32sin^2(36°)+16sin^4(36°))/(4(1-sin^2(36°)))
=(25-40sin^2(36°)+16sin^4(36°))/(4(1-sin^2(36°)))
=(25-40sin^2(36°)+20sin^2(36°)-5)/(4(1-sin^2(36°)))
=(20-20sin^2(36°))/(4(1-sin^2(36°)))=5
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