>>799
{(e^x)sin(x)}'=(e^x)sin(x)+(e^x)cos(x)=(√2)(e^x)sin(x+π/4)
{(e^x)sin(x)}''=(√2)(e^x)sin(x+π/4)+(√2)(e^x)cos(x+π/4)=(√2)(√2)(e^x)sin(x+π/4+π/4)
n回微分するとどうなるか・・・なんとなくわかるだろ