ZΆΜ½ίΜwΜΏβXPART225
‘ ±ΜXbhΝίOqΙΙi[³κΔ’ά·
0035PRQlΪΜf³ρ
2009/03/10(Ξ) 22:33:46I =η[0,3] 9sinΖcosΖdx
x=3nΖΎ©ηdx/dΖ=3cosΖAx:0¨3ΕΖ:0¨Ξ/2
I =η[0,Ξ/2]9sinΖcosΖ* 3cosΖdΖ
= η[0,Ξ/2]27sinΖicosΖjO2dΖ
sinΖ=-(cosΖ)' Ύη
= 27*[(-1/3)(cosΖ)^3] [0,Ξ/2]
=9
ΰΖΜ`ΕβιΘη
I = η[0,3] xγi9-xO2j
i9-xO2jOi3/2j = i3/2ji-2ji9-xO2jOi1/2j = -3xγ(9-x^2) Ύ©η
νΟͺΦγ(9-x^2) Μ΄nΦΝi-1/3ji9-xO2jOi3/2j+C
±κπF(x)Ζ·ιΖ
I = F(3)-F(0) = 0+i1/3j*9Oi3/2j = i1/3j*27 = 9
ͺΎΖu·ΉΈΙΰΕ«ι―ΗB
‘ ±ΜXbhΝίOqΙΙi[³κΔ’ά·