>>610
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dy/dx=2(sin2x)・(sin2x)' = 2(sin2x)・(cos2x)・(2x)' = 4(sin2x)(cos2x)

�A
1/(cosx)^2 = (cosx)^(−2)と考えて
dy/dx = −2(cosx)^(−3)・(cosx)' = −2(cosx)^(−3)・(-sinx)