>>921
(1) x^3 -1 = (x-1)(x^2 +x+1),
(2) x^m -1 = (x-1){x^(m-1) + x^(m-2) + ・・・・ + x +1},
  x=n^3 とおくと、
  n^(3m) -1 = (n^3 -1){n^(3m-3) + (n^(3m-6) + ・・・・ + n^3 + 1}
       = (n^2 +n+1)(n-1){n^(3m-3) + n^(3m-6) + ・・・・ + n^3 + 1},
 与式 = (n^2 +n+1)n^(3m-1) - {n^(3m) -1}
    = (n^2 +n+1){n^(3m-1) - (n-1)[n^(3m-3) + ・・・・ + n^3 +1]},

うーむ、どこが難しい??