>>642
a[k]=a+(k-1)d , S[n]=an+(1/2)n(n-1)d
lim[n→∞]S[n]/n^2=ー1 から d=-2
a[k]=a-2(k-1) , T[n]=2^a*{1-(1/2)^(2n)}/{1-(1/2)^2}=(1/3)*2^(a+2)*{1-(1/2)^(2n)}
lim[n→∞]T[n]=1/6 から a=-3