①∫xlogxdx
=∫((1/2)x^2)'logxdx
=(1/2)x^2logx-∫(1/2)x^2(1/x)dx
=(1/2)x^2logx-(1/4)x^2+C

②∫(x+1)e^xdx
=∫(x+1)(e^x)'dx
=(x+1)(e^x)-∫e^xdx
=e^x(x+1)-e^x+C
=xe^x+C

この二つはどっちも正解？