>>784
∫{0,2}[√(8-x^2) - {(1/2)(x-2)^2 - 2}]dx + ∫{2,2√2} 2√(8-x^2) dx
=8π - ∫{0,2}[√(8-x^2) - {-(1/2)(x-2)^2 + 2}]dx