本が新過程用ぢゃないけど許してｗ
{e^(x^2)-1}/(1-cosx)
=[{e^(x^2)-1}/(x^2)]*x^2*{(1+cosx)/(1-cos^2(x))}
lim {e^(x^2)-1}/(x^2)
=(e^u)'[u=0]
=e^u[u=0]
=1