>>338
∬xy^2dxdy
=∫[y:-1→0]∫[x:-y→2+y](xy^2)dxdy+∫[y:0→1]∫[x:y→2-y](xy^2)dxdy
=∫[y:-1→0](1/2){(2+y)^2-y^2}(y^2)dy+∫[y:0→1](1/2){(2-y)^2-y^2}(y^2)dy
=∫[y:-1→0](2+2y)(y^2)dy+∫[y:0→1](2-2y)(y^2)dy
=∫[y:-1→0](2y^2+2y^3)dy+∫[y:0→1](2y^2-2y^3)dy
=2/3-1/2+2/3-1/2
=1/3